Physics, asked by fadilahkhanA, 2 months ago

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i forgot to attatch this in my previous question... ​

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Answered by jaidansari248
2

 \int _{ \frac{\pi}{2} } ^{0}  \frac{1 +  \cos(2t) }{2}  \: dt \\  \frac{1}{2}  \int _{ \frac{\pi}{2} } ^{0}  \{1 +  \cos(2t)   \}\: dt \\  \frac{1}{2}  \{  \int _{ \frac{\pi}{2} } ^{0} dt +  \int _{ \frac{\pi}{2} } ^{0}  \cos(2t)  dt\} \\  \frac{1}{2}  \{ \: t  |  ^{0}  _{ \frac{\pi}{2}   }  +   \frac{ \sin(2t) }{2} |  {}^{0}  _{ \frac{\pi}{2} } \} \\  \frac{1}{2}  \{ \: 0 -  \frac{\pi}{2}  +  \frac{ \sin(0) }{2}  -  \frac{ \sin( \frac{\pi}{2} ) }{2}  \} \\  \frac{1}{4}  \{ - \pi  -  1) \\  =  \frac{ - (\pi + 1)}{4}

Answered by shukladivyansh076
0

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