Math, asked by sophia05, 9 months ago

no spam plz solve it​

Attachments:

Answers

Answered by pal69
2

see in attachment.

mark as Brainlist answer.

Attachments:
Answered by zahaansajid
3

To solve this problem we use the principle of

Heat lost by one substance = Heat gained by the other

One substance loses heat and cools down to temp t from t¹

Other substance gains heat and heats up to temp t from t²

Therefore, t¹>t>t²

Heat lost by one = m¹s¹∆T¹ = m¹s¹(t¹-t)

Heat gained by other = m²s²∆T² = m²s²(t-t²)

m¹s¹(t¹-t) = m²s²(t-t²)

m¹s¹t¹-m¹s¹t = m²s²t-m²s²t²

m¹s¹t¹+m²s²t = t(m¹s¹+m²s²)

t  =  \frac{ {m}^{1} {s}^{1} {t}^{1}   +  {m}^{2} {s}^{2}   {t}^{2}  }{m {}^{1} {s}^{1}   +  {m}^{2} {s}^{2}  }

Hope this is helpful to you

Pls mark as brainliest

Follow me and I'll follow you back

Similar questions