Question

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Solve for a:

7+42 times 3^2-3a = 14 times (3^-2a) +7

Answer 1

Answer:

7+42*3^(2-3a)=14*3^(2a)+7

We move all terms to the left:

7+42*3^(2-3a)-(14*3^(2a)+7)=0

We add all the numbers together, and all the variables

42*3^(-3a+2)-(14*3^2a+7)+7=0

Wy multiply elements

126a(--(14*3^2a+7)+7=0

We use the square of the difference formula

126a(+(14*3^2a+7)+7=0

Answer 2

Step-by-step explanation:

7+42⋅32−3a=14⋅3−2a+7

2a+7

Graph each side of the equation. The solution is the x-value of the point of intersection.

a≈3,17.3