Question

no spaming... spaming will be reported​

Answer 1

Answer:

yes

Step-by-step explanation:

QR = SD

(opposite sides of a parallelogram)

DQ = RS

(opposite sides of a parallelogram)

SQ = QS

(common side)

hence triangle SQD is congruent to triangle QSR

(BY SSS CONGRUENCE)

OR

angle RQS = angle DSQ

(alt. int. angles)

angle QSR = angle SQD

(alt. int. angles)

SQ = QS

(common side)

hence triangle SQD is congruent to triangle QSR

(BY ASA CONGRUENCE)

OR

angle QRS = angle SDQ

(opposite angles of parallelogram)

DQ = RS

(opposite sides of a parallelogram)

SQ = QS

(opposite sides of a parallelogram)

hence triangle SQD is congruent to triangle QSR

(BY SAS CONGRUENCE)

here's your answer