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A dome of a building is in the form of a hemisphere. From inside, it was white-washed at the cost of ₹498.96. If the cost of white-washing is ₹2.00 per square metre, find the radius of dome​

Answer 1

Answer:

Answer. the inner surface area of the dome is nothing but the total cost of whitewashing divided by the rate per metre. hence inner surface area= 498.96 / 2 = 249.48 m^2.

Answer 2

Cost of white washing dome = Rs.498.96

Cost of white washing 1m² area = Rs.2

$\sf \: CSA= \frac{498.96}{2} = 249.48 \: {m}^{2}$

Let, radius = r ,CSA =249.48 m²

$\sf \: CSA= 2\pi {r}^{2}$

$\sf \:249.48= 2 \times 3.14 \times {r}^{2}$

$\sf {r}^{2} = 37.9 \: {m}^{2}$

$\sf \: r = 6.3 \: m$