Question

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Answer 1

Answer:

given :

x^⅓ +y^⅓ +z^⅓= 0

identity-

if a+b+c = 0, then

a³+b³+c³ = 3abc

so,

(x^⅓)³ + (y^⅓)³ + (c^⅓)³ = 3 (x^⅓× y^⅓ ×z^⅓)

x+y+z = 3x^⅓ y^⅓ z^⅓

option (b)

Answer 2

$\bf\underline\blue{Answer\::-}$

If ${x}^{ \frac{1}{3} } + {y}^{ </strong><strong>\</strong><strong>f</strong><strong>r</strong><strong>a</strong><strong>c</strong><strong>{</strong><strong>1</strong><strong>}</strong><strong>{</strong><strong>3</strong><strong>}</strong><strong>} + {z}^{</strong><strong>\</strong><strong>f</strong><strong>r</strong><strong>a</strong><strong>c</strong><strong>{</strong><strong>1</strong><strong>}</strong><strong>{</strong><strong>3</strong><strong>}</strong><strong>}$

then ${x}^{3} + {y}^{3} + {z}^{3} = 3xyz$