Question

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A block of mass 500kg starts from rest and moves with speed of 10 m/s within 5 seconds. find force acting on the block​

Answer 1

Given

A block of mass 500 kg starts from rest and moves with speed of 10 m/s within 5 seconds

To Find

Force acting on the block

Solution

We know that

$\rm \longrightarrow F=m \times a$

$\rm \longrightarrow a=\bigg(\dfrac{v-u}{t}\bigg)$

Hence

By equating 'a'

We get

$\rm \longrightarrow F=m \times \bigg(\dfrac{v-u}{t}\bigg)$

Here

• F = Force
• m = Mass
• a = Acceleration
• u = Initial velocity
• v = Final velocity
• t = Time

Units

• F = Newton (N)
• m = kilogram (kg)
• a = metre/square second (m/s²)
• u = metre/second (m/s)
• v = metre/second (m/s)
• t = second (s)

According to the question

We are asked to find the force acting on the block

Therefore

We must find "F"

Given that

A block of mass 500 kg starts from rest and moves with speed of 10 m/s within 5 seconds

Hence

• m = 500 kg
• u = 0 m/s [starts from rest]
• v = 10 m/s
• t = 5 s

Substituting the values

We get

$\rm \longrightarrow F=500 \times \bigg(\dfrac{10-0}{5}\bigg) \ N$

$\rm \longrightarrow F=500 \times \bigg(\dfrac{10}{5}\bigg) \ N$

$\rm \longrightarrow F=100 \times 10 \ N$

Therefore

$\rm \longrightarrow F=1000 \ N$

Hence

Force acting on the block = 1000 N