Question

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A body, when acted upon by a force of 10 kgf, gets displaced by 0.5m. Calculate d work done by d force, when d displacement is 1) in d direction of force 2) at an angle of 60° with d force 3) normal to d force. ( take g = 10 N kg-1 )

Answer 1

Given ,

Force = 10 Kgf = 10×g Newton

where g is acceleration due to gravity .

taking g= 10m/s² ;

Force = 100N .

Displacement = 0.5m

Then,

WORK DONE = FORCE ×DISPLACEMENT

= 100×0.5 = 50J

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Hope it helps !

Answer 2

Check this attachment :-)