Question

❌❌ NO SPAMMING ❌❌

Derive the expression for kinetic energy...!!!!

Answer 1

__________________________________

• Consider a body of mass M moving with uniform acceleration along a straight line. If u is the initial velocity of a body, V is final velocity and S is distance covered by the body during this change of velocity, we have

__________________________________

${u}^{2}- {v}^{2} = 2as$

$S = {V}^{2} - {U}^{2}$

__________________________________

• If f is the net force acting on the body and w is the work done by the force

$W = Fs$

$Now , \: F = ma$

From equation 1 , 2 and 3 we get

W = ma × v² - u² = 1m (v² - u²)

__________________________________

• For a body initially at rest , $U = 0$

Therefore w = ½ mv²

• Work done on a body = change in the kinetic energy of the body.

• Therefore kinetic energy of a body = ½ mv²

__________________________________