Question

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❤☺Find the 31st term of an A.P. whose 11th term is 38 and 6th term is 73❤☺

Answer 1

Heya !
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♦Arithmetic Progressions ♦
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↪Given that :-
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=> A11 = 38

=> A6 = 73

◾A + 10D = 38 ------------------(1)

◾A + 5D = 73--------------------(2)

✔Solving (1) and (2) by ELIMINATION :-

=> 5D = 35

=> D = 7
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✔Put D = 7 in (1)

◾A + 10(7) = 38

◾A +70 = 38

◾A = 38 -70

=> A = -32
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➰AP becomes ,
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↪First term A = -32

↪Common Difference D = 7

♦A31 = A + 30D

=> -38 + 30(7)

=> 178

=> A30 =178
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Answer 2

$<b>Solution:$

♥ Refer to the attachment above for your answer.

♥ thanks for the question!