Question

no spamming give answer correct ​

Answer 1

Answer -

$\frac{ - b}{a}$

Explanation -

$let \: \alpha \: and \: 0 \: and \:0 \: be \: the \: zeroes \: of \: {ax}^{3} + {bx}^{2} + cx + d \\ then \: sum \: of \: zeroes \: = \frac{ - b}{a} = > \alpha + 0 + 0 = \frac{ - b}{a} = > \alpha = \frac{ - b}{a} \\ hence \: the \: third \: zero \: is \: \frac{ - b}{a}$

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Answer 2

Explanation:

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