Question

❌ No spamming

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∆™ I have given an attachment with only two types can u write the remaining

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✔ Plz do answer correctly

Answer 1

tan=sin/cos
cot=cos/sin
cosec=1/sin
sec=1/cos
sin=1/cosec
cos=1/sec
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

Answer 2

Hey dear !!!

⭐ This all are the relationship between Trigonometric ratio with right angled triangle.


Some of them are as follows : ⏬⏬⏬


cos (90- theta ) = sin theta

sin(90- theta ) = cos theta

sin tetha/cos theta = tan theta

tan tetha x cos theta = sin theta

sin theta x tan theta = cos theta

tan theta x tan (90- theta ) = 1


1/ sin theta = cosec theta


1/cos theta = sec theta


1/tan theta = cot theta


cosec theta x sin theta = 1 or cosec theta x 1 = sin theta


sec theta x cos theta = 1 or sec theta x 1 = cos theta


cot theta x tan theta = 1

cot theta x 1 = tan theta or 1/ tan theta= cot theta



sin theta ^2 + cos theta ^2 = 1


sec theta = cosec (90-theta )


cosec theta = sec(90-theta)

tan theta = cot (90-theta)

cot theta = tan (90- theta)


⭐ Some relation between negative angle trigonometric ratio. ⏬⏬⏬


sin ( - theta ) = - sin theta

cos ( - theta ) = cos theta

tan ( - theta) = - tan theta

cot ( - theta) = - cot theta

sec ( - theta ) = sec theta

cosec ( - theta ) = - cosec theta


Hope this will help you !!!


Thanks!!! ☺☺




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