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Mr. Dinesh owns an agricultural farm. The length of the farm is 10 metres more than twice the breadth. In order to harvest rainwater, he dug a square shaped pond inside the farm. The side of the pond is 1/3 of the breadth of the farm. The area of the farm is 20 times the area of pond. Find the length and breadth of the farm and of the pond.
Answers
Answered by
36
for farm,
length = 100 m
breadth = 45 m
for pond,
side = 15 m
step-by-step explanation:
Let,
the length of the farm be ' l '
the breadth of the farm be ' b '
and
the side length of the pond be 'a '
Now,
A.T.Q,
length of the farm is 10 metres more than twice the breadth
=> l = 2b + 10 ................(i)
also,
side of the pond is 1/3 of the breadth of the farm
=> a = b/3 ...............(ii)
again,
area of the farm is 20 times the area of pond
=> l × b = 20()
putting the values of 'l' and 'a' from eqn (i) and (ii),
we get,
=> b × (2b + 10) = 20
=> 2 + 10b = 20/9
doing cross- multiplication,
we get,
=>18 + 90b= 20
=> 2 - 90b = 0
=> 2b(b - 45) = 0
=> b = 0 or b = 45
°.° b is length , it can't be 0
.°. b = 45 m
Now,
putting the value of b in eqn (i),
we get,
l = 2×45 + 10 = 90+10 = 100 m
again,
putting the value of b in eqn (ii),
we get,
a = 45/3 = 15 m
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BrainlyVirat:
Thank you so much!
Answered by
46
Answer:
100 m, 45 m, 15 m.
Step-by-step explanation:
(i)
Let the breadth of the farm be 'x' metres.
Then the length of the farm = 2x + 10.
∴ Area of the farm = x(2x + 10)
= 2x² + 10x.
(ii)
Given that he dug a square of inside the farm, side of pond is (1/3) of breadth = (1/3) * x = (x/3).
∴ Area of pond = (x/3)²
= x²/9.
(iii)
Given that Area of farm is 20 times the area of pond.
⇒ 2x² + 10x = 20(x²/9)
⇒ 2x² + 10x = 20x²/9
⇒ 18x² + 90x = 20x²
⇒ -2x² = -90x
⇒ x = 45.
When x = 45:
Length = 2x + 10 = 100 m
When x = 45:
Side of pond = x/3 = 15.
Therefore:
∴ Length of the farm = 100 m.
∴ Breadth of the farm = 45 m.
∴ Side of the farm = 15 m.
Hope it helps!
100 m, 45 m, 15 m.
Step-by-step explanation:
(i)
Let the breadth of the farm be 'x' metres.
Then the length of the farm = 2x + 10.
∴ Area of the farm = x(2x + 10)
= 2x² + 10x.
(ii)
Given that he dug a square of inside the farm, side of pond is (1/3) of breadth = (1/3) * x = (x/3).
∴ Area of pond = (x/3)²
= x²/9.
(iii)
Given that Area of farm is 20 times the area of pond.
⇒ 2x² + 10x = 20(x²/9)
⇒ 2x² + 10x = 20x²/9
⇒ 18x² + 90x = 20x²
⇒ -2x² = -90x
⇒ x = 45.
When x = 45:
Length = 2x + 10 = 100 m
When x = 45:
Side of pond = x/3 = 15.
Therefore:
∴ Length of the farm = 100 m.
∴ Breadth of the farm = 45 m.
∴ Side of the farm = 15 m.
Hope it helps!
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