Question

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Answer 1

Question:$\:\:\:\:\:\:\:\:\:$ Find the least number that should be added to 9108 to make a perfect square.Also,find the square root of the number so obtained.

Solution:

We find $\sf{\sqrt{9108}}$ by long divison method.

$\:\:\:\:\:\:\:\:\:$

The remainder is 0 and the quotient is 253.

$\:\:\:\:\:\:\:\:\:$

This shows that, $\sf{253}^{2}$ < 9108.

$\:\:\:\:\:\:\:\:\:$

$\sf{95}^{2}$ = 9026

$\sf{{96}^{2}}$ = 9216

$\:\:\:\:\:\:\:\:\:$

But 9108 doesn't have a perfect square.

Required Answer:

• 9018 is not a perfect square.