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Division algorithm stated that a polynomial f(x) can written as
f(x)=g(x)q+r where q and r are unique integer and 0<=r<g(x).
Here,
g(x)=2x+3 and r(x)=x−1
The power of the remainder is always less than the power of the divisor
Here, the degree of remainder is 1 and the degree of divisor is 1, which is not possible. Thus, (x−1) cannot be the remainder of p(x) when divided by (2x+3)
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no, x - 1 cannot be remainder for given polynomial.
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