Question

no spams ..corrct answer nd asap ...pls solve

Answer 1

40×5/18= 11.11 m/s is the velocity of train..
acc=velo/time
=11.11m/s/600s
=0.0185 m/s^2
will be the acceleration...

Answer 2

here, u =0
v= 40 km/h or
$v =40 \frac{5}{18} \: \: \: \: m/s$
and t =10 mins or 600 secs

by first equation of motion,
$v = u + at$
therefore, plugging the values aa given in it,
$40 \frac{5}{18} = 0 + a(600)$
$\frac{5}{18} = 15a$
or,
$\frac{1}{18} = 3a$
or,
$a = \frac{1}{18} \: \: m/ {s}^{2}$