Question

No spams please. Please answer this fast.

Answer 1

Answer:

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Answer 2

$\frac{ \sqrt{3} + i \sqrt{2} }{2 \sqrt{3} + i \sqrt{2} } \\ \\ multiply \: and \: divide \: by \: conjugate \\ of \: denominator.... \\ \\ \frac{ \sqrt{3} + i \sqrt{2} }{2 \sqrt{3} + i \sqrt{2} } \times \frac{2 \sqrt{3} - i \sqrt{2} }{2 \sqrt{3} - i \sqrt{2} } \\ \\ \frac{6 + 2i \sqrt{6} - i \sqrt{6} -2 ( {i}^{2}) }{12 -2 ( {i}^{2}) } \\ \\ \frac{6 + i \sqrt{6} + 2 }{14} \\ \\ \frac{8 + i \sqrt{6} }{14} .....(1) \\ \\ compare \: (1) \: with \: x + iy \\ \\ \frac{8}{14} + \frac{ i\sqrt{6} }{14} \\ \\ then \: x \: = \frac{8}{14} \\ \\ and \: y = \frac{ \sqrt{6} }{14}$

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NICE ANSWER RISHU BHAIYA