no spams......solve it plz
Answers
Answer:
Step-by-step explanation:
GIVEN=
DISTANCE BTW THE POINT=√10
GIVEN POINT=(4,3)
AND POINT A HAS ITS ORDINATE TWICE OF ITS ABSISCA
TO FIND=
CORDINATES OF POINT A
SOLUTION=
LET THE ABSSISCA OF POINT A BE X
A=(X,2X)
X CORDINTES OF POITS =
X1=4
X2=X
Y CORDINATES=
Y1=3
Y2=2X
DISTANCE=√(X2-X1)²+(Y2-Y1)²
√10=√(X-4)²+(2X-3)²
SQUARING BOTH SIDE
10=5X²-20X+25
5X²-20X+15=0
5(X²-4X+3)=0
BY SPLITING MIDDLE TERM WE GET
5(X-3)(X-1)=0
X-3=0 & X-1=0
X=3,1
Y=6,2
THEREFORE THERE ARE TWO SUCH POINTS POSSIBLE
(3,6) &(1,2)
HOPE IT HELPS U BUDDY✌✌
Step-by-step explanation:
Answer:
Step-by-step explanation:
GIVEN=
DISTANCE BTW THE POINT=√10
GIVEN POINT=(4,3)
AND POINT A HAS ITS ORDINATE TWICE OF ITS ABSISCA
TO FIND=
CORDINATES OF POINT A
SOLUTION=
LET THE ABSSISCA OF POINT A BE X
A=(X,2X)
X CORDINTES OF POITS =
X1=4
X2=X
Y CORDINATES=
Y1=3
Y2=2X
DISTANCE=√(X2-X1)²+(Y2-Y1)²
√10=√(X-4)²+(2X-3)²
SQUARING BOTH SIDE
10=5X²-20X+25
5X²-20X+15=0
5(X²-4X+3)=0
BY SPLITING MIDDLE TERM WE GET
5(X-3)(X-1)=0
X-3=0 & X-1=0
X=3,1
Y=6,2
THEREFORE THERE ARE TWO SUCH POINTS POSSIBLE
(3,6) &(1,2)
HOPE IT HELPS U BUDDY✌✌