Question

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●JEE level Question.
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Answer 1

Answer:

(3)

Explanation:

Lets say the particle comes to point B in time 't'

Now we can see that the horizontal component of displacement in time t is zero as the particle is coming to the same x coordinate

Initialy,

x component of velocity,

Vx = usin($\theta$)

x component of acceleration

Ax = a

using $s = ut + \frac{1}{2} at^{2}$,

0 = $-usin$$\theta$$.t$ + $\frac{1}{2}at^{2}$

⇒ $t = \frac{2usin\theta}{a}$