Question

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Best answer would get brainliest
If alpha and beta are the zeroes of the equation 6x^2+x-2=0,find alpha/beta+beta/alpha

Answer 1

Hi there!

Given Eqn. 6x² + x - 2 = 0

Sum of zeroes, $\alpha$ + $\beta$ = -b/ a = -1 / 6

Product of zeroes, $\alpha$ × $\beta$ = c/ a = -2/ 6 = -1 / 3

ATQ,

$\alpha$ / $\beta$ + $\beta$ / $\alpha$

$\alpha^2$ + $\beta^2$ / $\alpha$ × $\beta$

( $\alpha$ + $\beta$ )² - 2 × $\alpha$ × $\beta$ / $\alpha$ × $\beta$

(-1/6)² - 2 × (-1/3) / -1/3

[ 1/36 + 2/3 ] / -1/3

13/36 × (-3)

-13/ 12

[ Thank you! for asking the question. ]
Hope it helps!