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A dice is thrown twice. Find the probability of getting a bigger value on the first throw
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Chakshu290703:
U mean the biggest?
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Dice throw two times it means possible outcomes = 36×2 = 72
FAVOURABLE OUTCOMES = 3
P(E) getting a bigger Number = Favourable outcomes/Possible outcomes = 3/72 = 1/24
FAVOURABLE OUTCOMES = 3
P(E) getting a bigger Number = Favourable outcomes/Possible outcomes = 3/72 = 1/24
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please find the answer
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