Math, asked by themasterthinkerx, 3 months ago

Nobody can solve this question!

An alloy is made from a mix of copper and tin.
The density of copper is 8.94 grams percm³.
The density of tin is 7.3 grams percm³.
500 cm³ of the alloy is made from 360 сm³ of copper with 140 cm³ of tin.
Work out the density of the alloy to 3 s.f.​

Answers

Answered by pretty938
0

AnswerMass of copper deposited =density×volume=8.94×1=8.94 gm.

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ=

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94=

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×96500

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q

Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q So, Q=27172 Coulomb.

Similar questions