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An alloy is made from a mix of copper and tin.
The density of copper is 8.94 grams percm³.
The density of tin is 7.3 grams percm³.
500 cm³ of the alloy is made from 360 сm³ of copper with 140 cm³ of tin.
Work out the density of the alloy to 3 s.f.
Answers
AnswerMass of copper deposited =density×volume=8.94×1=8.94 gm.
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ=
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94=
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×96500
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q
Mass of copper deposited =density×volume=8.94×1=8.94 gm.So according to faraday's law:W=ZQ= 96500E ×Q ⟹8.94= 2×9650063.5×Q So, Q=27172 Coulomb.