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Answered by
0
Answer:
5400 is the answer
Step-by-step explanation:
let's take the LCM of numbers
i.e. 5400
ihaveaquestion6:
show me proces
Answered by
5
1) Take the LCM of 7,14,and 8.It is 56.Now the multiples of 56 between 950 and 1050 are
952 and 1008.(only multiples of 56 will give remainder zero when it will be divided by the 7,14,and 8). The number which will give the remainder 6 when divided by the 7,14,and 8 will be 958 and 1014.(No will just 6 more than the multiples of 56)
So the answer is 2......
2) The Largest number of four digits is 9999.
Required number must be divisible by L.C.M. of 12,15,18,27 = 540.
On dividing 9999 by 540, we get 279 as remainder .
Required number = (9999-279) = 9720.
Hence, required largest number is 9720.
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