Math, asked by ihaveaquestion6, 10 months ago

NØ ØNE IS HERE TO GIVE ME ANSWER OF THIS TWO QUESTIONS???? ⚡ ⚡ ⚡

If anyone know then answer....
NOTE >Solve both questions

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Answered by vishu1727
0

Answer:

5400 is the answer

Step-by-step explanation:

let's take the LCM of numbers

i.e. 5400


ihaveaquestion6: show me proces
ihaveaquestion6: wrong answer
Answered by devanayan2005
5

1) Take the LCM of 7,14,and 8.It is 56.Now the multiples of 56 between 950 and 1050 are

952 and 1008.(only multiples of 56 will give remainder zero when it will be divided by the 7,14,and 8). The number which will give the remainder 6 when divided by the 7,14,and 8 will be 958 and 1014.(No will just 6 more than the multiples of 56)

So the answer is 2......

2) The Largest number of four digits is 9999.

Required number must be divisible by L.C.M. of 12,15,18,27 = 540.

On dividing 9999 by 540, we get 279 as remainder .

Required number = (9999-279) = 9720.

Hence, required largest number is 9720.

I hope you got your answer…

Pls mark brainliest


ihaveaquestion6: in first question I have doubt
devanayan2005: Ok ask
devanayan2005: Before that can you mark all other questions answerd by me brainliest
ihaveaquestion6: 952 and 1008 how??
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