Math, asked by angelpatel6909, 6 days ago

nometric2)tan A 1+sec A is equal to1+ sec A tan AA) 2cosec A B) 2sec AC)2sin A D) 2cos A​

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Answered by crazybot007
2

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Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Functions of Sum and Difference of Two angles

>>Prove that tanA1 + secA - tanA1 - secA

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Prove that

1+secA

tanA

1−secA

tanA

=2cosecA

Medium

Solution

verified

Verified by Toppr

LHS=

1+secA

tanA

1−secA

tanA

=

1−sec

2

A

tanA(1−secA)−tanA(1+secA)

=

−(sec

2

A−1)

tanA(1−secA−1−secA)

=

−tan

2

A

tanA(−2secA)

=

+sinA/cosA

+2/cosA

=

sinA

2

=3cosecA

Here's your answer dude

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