Question

nomial each with the given numbers as the sum and product of its
2. Find a quadratic polynomial each with the given numb
zeroes respectively.
0
-1
(m) 0,5
(iv) 1,1
(vi) 4,1​

Answer 1

Step-by-step explanation:

I solve 1 example

Then you can solve like this way

$let \\ \alpha = 4 \: \: \: \: \beta = 1 \\ \alpha + \beta = 4 + 1 = 5 \\ \alpha \beta = 4 \times 1 = 4 \\ the \: required \: quadratic \: equation \\ {x}^{2} - ( \alpha + \beta ) + \alpha \beta = 0 \\ {x}^{2} - 5x + 4 = 0$

Hope it helps you &

Thanks for the question ❣️❤️✌️✍️