Math, asked by svennela35, 5 months ago

Non exact differential equations
Solve: y2dx+(x2-xy-y2) dy​

Answers

Answered by kellycheungaims
1

Answer:

y^2.dx +(x^2-xy-y^2).dy = 0 dy/dx = -y^2/(x^2-xy-y^2)………………(1) Let y = v.x dy/dx = v.1 + x.dv/dx On putting dy/dx= v+x.dv/dx in eq.(1) v+x.dv/dx= -v^2.x^2 ...

Step-by-step explanation:

It is 22

Answered by thubetanuja1411
0

Step-by-step explanation:

y²dx=-(x²-xy-y²)dy

dx/dy=(-x²+xy+y²)/y²

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