Question

non parallel sides of trapezium are equal then it is triangle​

Answer 1

Step-by-step explanation:

then this is cyclic trapezium...plz mark me brainlist

Answer 2

Answer:

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Step-by-step explanation:

Given:

ABCD is a trapezium where non-parallel sides AD and BC are equal.

Construction:

DM and CN are perpendicular drawn on AB from D and C respectively.

To prove:

ABCD is cyclic trapezium.

Proof:

In △DAM and △CBN,

AD=BC       ...Given

∠AMD=∠BNC      ...Right angles

DM=CN     ...Distance between the parallel lines

△DAM≅△CBN   by RHS congruence condition.

Now,

∠A=∠B      ...by CPCT

Also, ∠B+∠C=180°      ....Sum of the co-interior angles

⇒∠A+∠C=180°

Thus, ABCD is a cyclic quadrilateral as sum of the pair of opposite angles is 180°.