Question

non parralel side of trapezium is 13 and 14 and parallel side are 10 and 25​

Answer 1

Answer:

Step-by-step explanation:

Hello,

let's look at the figure.

AB=10 cm;DF=25cm;AD=14cm; BF=13cm

we calculate the CF:

CF=DF-CD=25-10=15 cm

For ΔBCF,

we calculate the perimeter of triangle

P=BC+BF+CF=14+13+15=42 cm

we calculate the  semiperimeter of the triangle:

p=P/2=42/2=21 cm

we use the formula of Heron:

At=√p×(p-BC)×(p-BF)×(p-CF);

=√21(21-14)(21-13)(21-15)

=√21×7×8×6=√7056= 84 cm²

we calculate the height of triangle:

BE=2At:CF=(2×84):15=168:15=11.2 cm

we calculate the area of Trapezium

A =[(AB+DF)×BE):2=[(10+25)×11.2]:2=(35×11.2):2=392:2=196 cm²

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