Non-stoichiometric compound Fe0.94O is formed when x% of Fe2+ ions are replaced by as many 2/3rd Fe3+ ions, x is?
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9
Answer:
18%
Explanation:
Non-stoichiometric compounds are the chemical compounds, that are always solid inorganic compounds and have an elemental composition whose proportions can't be represented by integers
Non-stoichiometric compound = Fe = 0.94O (Given)
The number of Fe3+ ions replacing x Fe2+ ions = 2x/3 vacancies of the cations
The molecule is neutral therefore net positive = net negative
= x − 2x/3 =x/3
But x/3 =1−0.94
=0.06,
x = 0.06×3
= 0.18
= 18%
Thus, the ions replaced are 18%
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