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11. If x + y + z = 13 and x2 + y2 +
z2 = 69, then xy + z (x + y) is
equal to....... the answer
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Answer:
xy + z(x+y) = xy+yz+zx
x+y+z = 13
=> (x+y+z)² = 169
=> x²+y²+z² + 2(xy+yz+zx) = 169
=> 69 + 2(xy+yz+zx) = 169
=> 2(xy+yz+zx) = 100
=> xy + yz + zx = 50
=> xy + z(x+y) = 50
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