Chemistry, asked by rittikashaw10, 7 months ago

Nootan ISC Chemistry-XII
.14 A conductivity cell when filled with 0.05 M solution
of KCl records a resistance of 410.5 ohm at 25°C
When filled with CaCl2 solution (11 g in 500 ml),
it records a resistance of 990 ohms. If
specific
conductance of 0.05 M KCl is 0.00189 ohm cm
calculate (1) cell constant; (ii) specific conductance
of CaCl2; (iii) equivalent conductance of CaCl,
solution; (iv) molar conductance of CaCl2 solution.
(Ans. () 0.7758 cm 67.84 10- ohm cm' om
1.98 ohm-1m -1
-1 2
(iv) 396​

Answers

Answered by sunil7798903166
0

Answer:

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