Question

Nora leaves Town A and walks towards Town B at a speed of 100m/min.
at the same time kate n Lixin walk from Town B t toward town A, at a speed of 80m/min n 75m/min respectively.
if Nora meets Lixin 6 min.after passing kate. Which means Nora meets Kate first before Lixin. Find the distance from A to B.

Answer 1

Answer:

Sit at home now

Step-by-step explanation:

dont got Nora from town A to B

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Answer 2

Step-by-step explanation:

Let L be the distance between the cities and let "t" be the time (in minutes) from the start to the moment Nora meets Kate.

The first equation is

100*t + 80*t = L (1) (Nora's walked distance + Kate's distance = L at the moment they meet each other)

Also, the time from the start to the moment Nora meets Lixin is (t+6) minutes.

And the second equation is similar to the first one:

100*(t+6) + 75*(t+6) = L. (2) (Nora's walking distance + Lixin's distance = L at the moment they meet each other)

Equations (1) and (2) have equal right sides.

Hence, their left sides are equal, too:

100*t + 80*t = 100*(t+6) + 75*(t+6).

It is a single equation for one unknown "t". Simplify and solve for "t":

180*t = 175t + 600 + 300,

180t - 175t = 900,

5t = 900,

t = 900%2F5 = 180.

Thus we found the time "t" till the first meeting. It is 180 minutes.

Then the distance, according to the equation (1), is 100*180 + 80*180 = 32400 meters = 32.4 kilometers.

Answer. The distance between the cities is 32400 meters, or 32.4 kilometers.

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