Question

Nora works at a Drug Company as a chemist. To meet the clients demands, she was told to

prepare 100 liters of 25 % alcohol solution. They have on hand a 15 % solution and a 40%
solution which she thought of mixing. How many liters of each solution will be required to
make the mixture?​

Answer 1

Answer:

31.25, 18.75, 50

Step-by-step explanation:

firstly, calculate total % which is 25+15+40 = 80 %

25/80 × 100 = 31.25 liters

15/80 × 100 = 18.75 liters

40/80 × 100 = 50 liters

Answer 2

The required quantity of 15 %solution and   40% solution to make the mixture will be 60 liters and 40 liters respectively.

Step-by-step explanation:

Given:

15% solution  

40%solution

The resulting mixture is 100 liters of 25 % alcohol solution.

To Find:

The required quantity of  15% solution and   40% solution to make a mixture.

Formula Used:

Quantity of 15 %solution / Quantity of 40% solution   = ( Strength of 40%  solution -  Strength of 25 %mixture solution)  / (Strength of 25% mixture solution – Strength of 15% solution )------------ formula no..01

The above is per the rule of the allegation.

Solution:                    

Strength of  15%solution = 15%

Strength of  40% solution = 40%

Strength of 25 % mixture solution =  25%

Applying formula no.01.

$\frac{ Quantity\ of\ 15\%\ solution}{Quantity\ of\ 40\%\ solution} =\frac{( 40-25)}{(25-15)}$

                                     $= \frac{15}{10} =\frac{3}{2}$        

The quantity of  15 %solution $=\frac{3}{5} \times 100 \ liters$

                                                  $=\frac{300}{5} = 60\ liters$

The quantity of 40 %solution $=\frac{2}{5} \times 100 \ liters$

                                                 $=\frac{200}{5} = 40\ liters$

Thus, the required quantity of  15% solution and   40% solution to make the mixture will be 60 liters and 40liters respectively.