Question

normal molar mass of solute is 246 gmol -1 and observed molar mass of the same solute in a solvent is 346 gmol -1 what is the value of van't hoff factor​

Answer 1

Answer:

here

Explanation:

Osmotic pressure is one of the colligative property which plays a major role in a biological cell. An important factor that affects cells is osmotic pressure. Osmoregulation is an organism's homeostasis process for osmotic pressure to achieve equilibrium.  

• Hypertonicity is the presence of a solution that causes the shrinkage of cells.  
• The presence of a solution that causes cells to swell is hypotonicity.  
• Isotonicity is the presence of a solution that does not cause any change in the volume of cells.  

If the cell within accumulates water when a biological cell is in a hypotonic environment, water flows into the cell via the cell membrane, allowing it to expand. The cell wall limits expansion in plant cells, resulting in pressure from within on the cell wall called turgor pressure.

Answer 2

Given info : normla molar mass of solute is 246 g/mol and observed molar mass of the same solute in a solvent is 346 g/mol.

To find : the value of Van't hoff factor is ...

solution : Van't hoff factor , $\bold{i}=\frac{\text{normal molar mass}}{\text{observed molar mass}}$

here the normal molar mass = 246 g/mol

observed molar mass = 346 g/mol

∴ i = 246/346 = 0.7109

therefore the Van't hoff factor of the solute is 0.7109.

[ note : for solute showing association, the Van't hoff factor should be less than 1. here you see, the Van't hoff factor of solute is 0.7109 < 1. hence the given solute shows association. ]