Question

Normal molar mass of solute is 246gmol-1 and observed molar mass of the same solute in a solvent is. 346gmol-1. What is the value of Van't Hoff factor (i)?.​

Answer 1

Explanation:

observed /calcukated

=346/246

=1.4065

Answer 2

VAN'T OFF FACTOR -

• A factor that defines the effect of solute on the properties of a solution.
• The degree of dissociation or association of the solutes in the solution.
• It is also given as the ratio of substances formed or dissociates in the total concentration of the solution by mass.
• The van't hoff factor is calculated as -

$i = \frac{Normal Molar mass}{Observed Molar mass}$

• In the case of an association, the factor is less than 1 whereas in the case of dissociation of the particles the factor is more than 1.

GIVEN -

Normal molar mass = 246 g/mol

Observed molar mass = 346 g/mol

According to the equation,  i = $\frac{246}{346}$

i = 0.71