Question

Normal stresses in some section are σ= 360 MPa. To determine the value of relative deformations if Young's modulus is E = 90 GPa

Answer 1

Answer:

The value of relative deformation is $=4*10^{-3}$ Pa

Explanation:

Given:

Stress=$360$ MPa

$=360*10^{6}$ Pa

Young's modulus $E=90$ Gpa

$=90*10^{9}$ Pa

Strain is the deformation in that section

We know that

Young's modulus=$\frac{Stress}{Strain}$

$90*10^{9} =\frac{360*10^{6} }{Strain}\\Strain=\frac{360*10^{6} }{90*10^{9}}$

$=4*10^{-3}$ Pa