Question

normality and morality of 49g of H3PO4 dissloved in 500ml of solution

Answer 1

molarity of solution=1.1M
normality of solution= n into M 
                                 =3.3N
molarity=given mass divided by molecular mass into volume of solution in litres
normality = given mass divided by equivalent mass into vol. of sol. in litres
=49 × 1000÷(97 ×500)
=1.1