Question

Normality of 0.5 M H3PO4 solution is O 12N o 1.5N O'ON O 06N 0.8N​

Answer 1

Normality = Molarity /valency factor

For H3PO4 valency factor is 3 because it can give 3 H⁺ IONS.

∴Normality = 0.5/3

                    = 0.16

Answer 2

Given:

Molarity of the $H_{3}PO_{4}$ solution = 0.5

To find:

Normality = ?

Formula to be used:

Normality = Molarity × No. of replaceable hydrogen ions

Calculation:

The given compound  $H_{3}PO_{4}$ has 3 replaceable hydrogen ions.

Molarity is already given.

Now substitute the values in the following formula

Normality = Molarity × No. of replaceable hydrogen ions

Normality = 0.5 × 3

Normality = 1.5

Final answer:

Normality of 0.5 M $H_{3}PO_{4}$  solution is found as 1.5 N.