Question

normality of 2M sulphuric acid is....... explain a) 2N b) 4N c) N/2 d) N/4

Answer 1

Equivalent weight [E] of sulphuric acid = Molecular weight of sulphuric acid                                                                = M / (1×2) = M/2

So M = 2E
2M sulphuric acid means ,
1L solution contains 2M sulphuric acid
 = 2 × 2E Sulphuric acid
 = 4E Sulphuric acid = 4N Sulphuric acid

So the answer is b) 4N 

Answer 2

hope it will help you