Question

Normality of 7.4g of CaOH in 100 ml of solution is?​

Answer 1

Answer:

Normality = 1

Explanation:

Equivalent Weight of CaOH = 74

gram Equivalent = 7.4÷74 = 0.1

Normality = (0.1×1000)÷100

Normality = 1

Answer 2

Considering it Ca(OH)2, its molar mass is 74g, n-factor=2. Therefore, equivalent weight=molar mass/n-factor=74/2=37.
Therefore, no. of equivalence=7.4/37=0.2
100ml contains 0.2 equivalence
Therefore, normality=2
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