Question

Normality of 9.8 g of sulphuric acid in 250 ml of solution

Answer 1

normality= number of moles of solute/total no. of solvent (in kg)×100.......
put this formula u will get ur ans.

Answer 2

$\large\red { \mathfrak{nfactor \: = 2}} \\ \\ \large\red { \mathfrak{mass \: of \: solute \: = 9.8g}} \\ \\ \large\red { \mathfrak{molar \: mass = 98}} \\ \\ \large\red { \mathfrak{volume \: of \: solution = 250ml = 0.25l}} \\ \\ \large\red { \mathfrak{normality =(9.8 \times 2) /(98 \times 0.25) }} \\ \\ \huge\green{ \mathfrak{ \star \star \star \star0.8N \star \star \star \star}}$