normality of o.37 M of phosphorus acid is
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normality =molarity×basicity
=0.37×1 (basicity of phosphorus acid=1)
=0.37
=0.37×1 (basicity of phosphorus acid=1)
=0.37
amitchandra227:
0.6 is the answer
how
there are two posibality 1)hypo phosphorus acid -basicity =1and other is ortho phosphorus acid -basicity = 2 .so there are two answer first one is 0.37and second is 2×0.37=0.75
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