normality of solution obtained by mixing 200ml of N/10 HCl and 200 ml of N/20 HNO3
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Answer:
0.075
Explanation:
GIVEN- 200 ml of N/10 HCL
200 ml OF N/20 HNO3
PROVE - NORMALITY OF MIXING
FORMULA - N1 V1 + N2 V2 / V1 + V2
SOL-= 200 ml 0.1 N = HCl
=200 ml 0.05 N = HNO3
=PUTTING THE INFORMATION IN THE FORMULA WE GET-
=(200)(0.1) + (200)(0.05)/ 200+200
= 30/400 = 0.075
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