Question

Not got answersGive possible expression for the length and breadth of a rectangle with area 35y^2+13y-1

Answer 1

there is no possibility with this question
try with
$35 {y}^{2} + 12y + 1$
then
$35 {y}^{2} + 5y + 7y + 1 = 0 \\ 5y(7y + 1) + 1(7y + 1) = 0 \\ (5y + 1)(7y + 1) = 0 \\ therefore \: y = - \frac{1}{5} \: or \: - \frac{1}{7}$

Answer 2

Given Area:

35y²+13y-12

To Find :

Length and Breadth

Solution :

Factorising 35y²+13y-12

[By mid term spilting]

35y²+13y-12

35y²+28y-25y-12

7y(5y+4)-3(5y+4)

(5y+4) (7y-3)

Length = 7y-3

Breadth = 5y+4