not lactorable.
5. If a square pool is to be made a rectangle such that the length is increased by 6 and the width
is decreased by 6 units, what will happen to its area?
a. The area will increase by 12.
b. The area will decrease by 12.
c. The area will increase by 36.
d. The area will decrease by 36.
Answers
Step-by-step explanation:
Length of rectangle is reduced by 5 units and
its breadth is increased by 3 units and the
area of rectangle is reduced by 8 sq. units
(L−5)(W+3)=LW−8
LW+3L−5W−15=LW−8
3L−5W=7 __(1)
Length is reduced by 3 units and breadth is increased
by 2 units, then the area of Rectangle will be
67 sq. units increased
(L−3)(W+2)=LW+67
LW+2L−3W−6=LW+67
2L−3W=73 __(2)
Solving (1)×2 by (2)×3
2(3L−5W=7)→6L−10W=14
3(2L−3W=73)→6L−9W=219
−W=−205
W=205
W = 205 in eq (1).
3L−5(205)=7
3L=7+1025
3L=1032→L=
3
1032
L=344
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Answer:
option (d)
Step-by-step explanation:
let the side of sq be = x
area of sq = x²
let the length be = x+6
let the width be = x-6
therefore area = l×b
= (x+6)(x-6)
= x²-6²
= x²-36
hence the area will decrease by 36 units.