Question

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Answer 1

Answer:

r = 20√(5/2)m

Explanation:

F = Gm(1)m(2) ÷ r²

according to question

F(1) = 2 F(2)

=> G(40)(60) ÷ (20²) = 2×G(60)(50)÷ (r²)

=> r² = 2× (60)(50) ×(20²) ÷ { (40)(60)}

=> r² = (2×50/40) (20²)

=> r² = (100/40) (20²)

=> r = √(5/2) ×√(20²)

=> r = 20√(5/2)m

Answer 2

Answer:

how you know Atharv.....