Question

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Topic: Algebraic Expressions

Solve the following:



Q1. Write the following as formulas

(a) The perimeter (P) of a square is four times its side (s)

(b) The speed (s) of a vehicle is obtained by dividing the distance travelled (d) by the time taken (t)

(c) The selling price (SP)of an article is obtained by adding its cost price (CP) and profit(P)



Q2. Simplify the following

(a) x + 7 – ( y + 9)

(b) ( y – 2 ) – ( x + 5 )

(c) – ( x – y)

(d) ( a – 12 ) – ( b + 7 ) – ( c – 5 )



Q3. If x = 3 , y = – 2 and z = 5 find the value of the following

(a) 40 – 9 x2

(b) 3x2

– 4y2

+ 5 z2

(c) – x y z – 15

(d) x2

– y

3



Q4. Subtract

(a) 2ab from 6ab

(b) –3a2b from 7a2b

(c) 6a + 4b from 2a + 3b

(d) – 18abc from 20abc



Q5. If the side of a square is 2x + 3y, then find its perimeter.

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Answer 1

Answer:

a) 4a ( where a is side)

b) speed=Distance/Time

c) SP= CP+P

Step-by-step explanation:

a) x+7-(y+9)

= x+7-y-9

= x-y+7-9

=x-y-2

b) (y-2)-(x-5)

= y-2-x+5

= y-x-2+5

= y-x+3

c)-(x-y)

= -x+y

d) (a-12)-(b+7)-(c-5)

= a-12-b-7-c+5

= a-b-c-12-7+5

= a-b-c-19+5

= a-b-c-14

Q3.

x = 3

y = -2

z = 5

a) 40-9 x2

= 40-9*3*2

= 40-54

= -14

b)3x2

= 3*x*2

= 3*3*2

= 18

c)-4y square

= -4*-2*-2

= -16

Q4.

a) 6ab-2ab=4ab

baki khud kar