note on use of imagery in Ch 1 till 2 in white dolphin with textual evidences
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Explanation:
DE is parallel to AC
FG is parallel to BC
IH is parallel to AB
△PIE=49
△PDF=4
△PGH=9
△PGH≅△PIE
HP:PI=
9
:
49
=3:7
so, IP:IH=7:10
△PIE:△HIC=7
2
:10
2
area of △HIC=100
area of parallelogram PGCE=100−9−49=42
similarly,
are of parallelogram PIBF=(
4
+
49
)
2
−4−49
=81−53=28
are of parallelogram PDAH=(
4
+
9
)
2
−4−9
=25−13=12
are of △ABC=49+4+9+28+42+12=144
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