Question

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A surface with measures 80cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth. How many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases?

Answer 1

Answer:

Total surface area of a suitcase = 2(lb + bh + hl)

= 2(80 x 48 + 48 x 24 + 24 x 80)

= 2(3840 + 1152 + 1920) cm2

= 2(6912) cm2

= 13824 cm2

∴ Total S.A. of 100 suitcases = 100 x 13824 cm2 = 1382400 cm2

Surface area of 1 m of tarpaulin = 100 cm x 96 cm

= 9600 cm2

i.e. 1 m of tarpaulin can cover 9600 cm2 surface

∴ 1382400 over 9600 metres of tarpaulin will cover the total surfaces of 100 suitcases

i.e. 1 m of tarpaulin can cover 9600 cm2 surface

∴ 1382400/9600 metres of tarpaulin will cover the total surfaces of 100 suitcases

i.e. 1382400/9600 or 144 metres of tarpaulin will be required to cover 100 suitcases.

Answer 2

QuestioN :

A surface with measures 80cm × 48 cm × 24 cm is to be covered with a Tarpaulin cloth. How many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases?

GiveN :

• A surface with Measures 80cm × 48 cm × 24 cm.

To FiNd :

• How  many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?​

ANswer :

144 m of cloth is required to cover 100 suitcase.

SolutioN :

• Let length = l, breath = b and height = h
• Length of the suitcase = 80 cm
• Breath of the suitcase = 48 cm
• Height of the suitcase = 24 cm
• Total surface area of 1 suitcase

= 2( lb + bh + hl ) cm²

= 2( l x b + b x h + h x l ) cm²

= 2( 80 x 48 + 48 x 24 + 24 x 80 ) cm²

= 2( 3840 + 1152 + 1920 ) cm²

= 2 x 6912 cm²

= 13824 cm²

• Area of tarpaulin = 100 x Area of 1 suitcase

                                    = 96 x l = 100 x 13824

• ∴ Length = 100 x 13824 ÷ 96

                       = 14400 cm

                       = 14400 x 1 ÷ 100 m

                       = 144 m

∴Hence, 144 m of cloth is required to cover 100 suitcase.

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