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1) let x be angle
180°-x=130
180°-130°=x
x=50°
2)let the supplement angle be x
180°-(x+60°)=x
20°-x=x
2x=20°
x=10°
3)90°-65°=1/3x
25°×3=x
x=75°
4)180°-107°= 73°
180°-170°=10°
180°-53°=127°
5)let the supplement angle be x
180°- 4x=x
5x=180°
x=180/5=40°
x=36°
Hope it will help you
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